Content: 10278.png (24.27 KB)
Uploaded: 02.06.2022

Positive responses: 0
Negative responses: 0

Sold: 1
Refunds: 0

$0.98
Normal acceleration point, moving in a circle R = 4 m, is given by: a = 1 + 6t + 9t2 (m / s ^ 2). Define: tangential acceleration point, the path traversed by a point in time after the start of movement 5s full acceleration for the time t = 1 s.

Detailed solution shorthand terms, formulas, laws used in the decision, the withdrawal of the calculation formula and the response.

If you have any questions to address, please. I´ll try to help.
No feedback yet

Similar items