Content: 10165.png (20.23 KB)
Uploaded: 29.05.2022

Positive responses: 0
Negative responses: 0

Sold: 3
Refunds: 0

$1.01
Mokhovikov a solid disc, the moment of inertia is J = 1,5 kg * m2 rotating when braking ravnozamedlenno for time t = 1 min reduced the frequency of their rotation with n1 = 240 rev / min to n2 = 120 rev / min. To determine: 1) the angular acceleration of the flywheel; 2) the time of braking forces; 3) A brake job
Detailed solution shorthand terms, formulas, laws used in the decision, the withdrawal of the calculation formula and the response.
No feedback yet

Similar items